12x^2-700x+100=0

Solution for 12x^2-700x+100=0 equation:

12x^2-700x+100=0

a = 12; b = -700; c = +100;
Δ = b2-4ac
Δ = -7002-4·12·100
Δ = 485200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{485200}=\sqrt{400*1213}=\sqrt{400}*\sqrt{1213}=20\sqrt{1213}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-700)-20\sqrt{1213}}{2*12}=\frac{700-20\sqrt{1213}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-700)+20\sqrt{1213}}{2*12}=\frac{700+20\sqrt{1213}}{24}
$